Consider the following data in respect of the heat exchanger of a continuous washing range in a state of dunamic equilibrium at equal mass flow rates of both the thermic fluid and water (Assume that the exchange is circulating the fluid at its maximum capacity)
| Specific heat of the thermic fluid used | 2500 J/KgoC |
| Specific heat of water being heated | 4200 J/KgoC |
| Intel temperature of thermic fluid | Outlet temperature of ther oC |
| Outlet temperature of thermic fluid | 75 oC |
| Inlet temperature of water | 30 oC |
| Outlet temperature of water | 95 oC |
Question 89 (Textile Engineering & Fibre Science)
The efficiency of the heat exchanger is
| (A) | 0.47 |
| (B) | 0.67 |
| (C) | 0.87 |
| (D) | 0.97 |
[Show Answer]
Option C is correct
Heat In=Heat out
Heat of fluid=Heat of water
Efficiency of heat exchanger x specific heat of thermal fluid x temperature1=Specific heat of water x temperature2
Efficiency of heat exchanger x 2500 x (200-75)=4200 x (95-30)
Efficiency of heat exchanger x 2500 x 125=4200 x 65
Efficiency of heat exchanger=0.87