Consider the following data in respect of the heat exchanger of a continuous washing range in a state of dunamic equilibrium at equal mass flow rates of both the thermic fluid and water (Assume that the exchange is circulating the fluid at its maximum capacity)

Specific heat of the thermic fluid used | 2500 J/Kg^{o}C |

Specific heat of water being heated | 4200 J/Kg^{o}C |

Intel temperature of thermic fluid | Outlet temperature of ther ^{o}C |

Outlet temperature of thermic fluid | 75 ^{o}C |

Inlet temperature of water | 30 ^{o}C |

Outlet temperature of water | 95 ^{o}C |

###### Question 89 (Textile Engineering & Fibre Science)

The efficiency of the heat exchanger is

(A) | 0.47 |

(B) | 0.67 |

(C) | 0.87 |

(D) | 0.97 |

**[Show Answer]**

Option C is correct

Heat In=Heat out

Heat of fluid=Heat of water

Efficiency of heat exchanger x specific heat of thermal fluid x temperature1=Specific heat of water x temperature2

Efficiency of heat exchanger x 2500 x (200-75)=4200 x (95-30)

Efficiency of heat exchanger x 2500 x 125=4200 x 65

Efficiency of heat exchanger=0.87