###### Question 90 (Textile Engineering & Fibre Science)

If the maximum fluid circulating capacity of the above heat exchanger is 10^{4} kg/hr and the required temperature of water at the outlet is 75^{o}C, the maximum flow rate of water (kg/hr) at the outlet will be

(A) | 0.85 x 10^{4} |

(B) | 1.28 x 10^{4} |

(C) | 1.44 x 10^{4} |

(D) | 1.67 x 10^{4} |

**[Show Answer]**

Option D is correct.

Maximum flow rate of water x specific heat of water x temperature of water=Maximum fluid circulating capacity x specific heat of fluid x temperature of fluid

Maximum flow rate of water x 4200 x (75-30)= x 2500 x (200-75)

Maximum flow rate of water x 4200 x 45=x 2500 x 125

Maximum flow rate of water = x 1.65

Maximum flow rate of water =1.65 x