GATE (TF) Textile 2004 Question Paper Solution | GATE/2004/TF/49

Question 49 (Textile Engineering & Fibre Science)

A two ply yarn has a resultant count of 18s Ne. Assuming 10% twist contraction during ply twisting the yarn count (Ne) of single yarns used for ply twisting was

(A)	32
(B)	36
(C)	40
(D)	44

[Show Answer]

Option C is correct.
Resultant count of two ply yarn=18s Ne

Twist contraction=10%

Count of single yarn=?

Let, the ply yarn count before twiting=x

Then,

x-x.10%=18

0.9 x =18

x=20s Ne

Now,
Let,single count used for doubling=N

$\frac{1}{20}=\frac{1}{N}+\frac{1}{N}$

$\frac{1}{20}=\frac{2}{N}$

N=40s Ne (Ans)

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