GATE (TF) Textile 2005 Question Paper Solution | GATE/2005/TF/68

A 36 cotton yarn has an average strength of 300 cN with a CV of 12.5%.

The minimum number of samples which must be tested to obtain the average value of yarn strength with less than 5% error 95% of the items is

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oPTION c

Given-

CV=12.5%

SE=5%

Number of samples(N)=?

By formula-
95% confidence range-

$N=(\frac{1.96 \times CV}{SE} )^2$

$N=(\frac{1.96 \times 12.5}{5} )^2$

N=24