GATE (TF) Textile 2006 Question Paper Solution | GATE/2006/TF/43

CV (%) of 20 tex cotton combed yarn is 12.32%. If the cotton fibre fineness is 1.2 dtex, index of irregularity will be depend on

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Option B is correct.
Given-

Count of yarn=20tex

CV% of this yarn(CVeff)=12.32%

Cotton fibre fineness=1.2 dtex

Index of irregularity=?

By formula-

Index of irregularity= $\frac{CV_eff}{CV_lim }$

$CV_lim=\frac{106}{\sqrt N}$

Where N is the number of fibres in the yarn cross section

N=YARN COUNT/FIBRE COUNT

N=20/0.2
N=100

$CV_lim=\frac{106}{\sqrt 100}$

$CV_lim=\frac{106}{10}$

$CV_lim=10.6$

Now,
Index of irregularity= $\frac{12.32}{10.6}$

Index of irregularity=1.2

Index of irregularity=1.5 (Ans)

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