GATE (TF) Textile 2006 Question Paper Solution | GATE/2006/TF/61

The following data refers to a cone winding process:
– Package diameter = 20 cm
– Package height = 25 cm
– Drum diameter = 8 cm
– Scroll of the drum = 2.5
– Winding speed = 1000 m/min

Question 61 (Textile Engineering & Fibre Science)

The rpm of the drum is approximately

(A)	3,000
(B)	3,400
(C)	3,700
(D)	4,000

[Show Answer]

Option D is correct.
Given-

Package diameter = 20 cm
– Package height = 25 cm
– Drum diameter = 8 cm
– Scroll of the drum = 2.5
– Winding speed = 1000 m/min

By formula-

Winding speed= $\pi \times D \times N$

Where, D is the dia of drum and N is the rpm of the drum.

1000= $3.14 \times 8 \times 10^-2 \times N$

$N=\frac{1000}{3.14 \times 8 \times 10^-2}$

$N=\frac{1000}{0.2512}$

$N=3981$

The rpm of the drum(N)=4000 RPM (Ans)

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