Question 67 (Textile Engineering & Fibre Science)
With 500 mm specimen length, strain rate (% per min) on a tensile tester with 5 m/min jaw speed would be
| (A) | 500 |
| (B) | 1000 |
| (C) | 5000 |
| (D) | 10000 |
[Show Answer]
Option B is correct.
Given in the question-
Length of specimen=500 mm
Jaw speed=5 m/min
=5000 mm /min
Strain rate(% per min)=?
Strain rate(% per min)=Jaw speed x 100/Length of specimen
Strain rate(% per min)=5000 x 100/500
Strain rate(% per min)=1000 (Ans)