**Common Data Questions**

Assume that the “standard machine rate of loading” of a commercial tensile testing machine working on pendulum lever principle is 200 kgf/cm. The breaking load and extension of a sample tested at a gauge length of 20 cm is 50 kgf and 80% respectively. The velocity of the lower jaw is 0.50 cm/s.

###### Question 74 (Textile Engineering & Fibre Science)

The change in “machine rate of load” (kgf/cm) as pendulum lever swings by 30 degrees from its normal position, is

(A) | 100 |

(B) | 173.2 |

(C) | 346.4 |

(D) | 400 |

**[Show Answer]**

Option B is correct.

Given in the question-

Standard machine rate of loading()=200 kgf/cm

Gauge length=20 cm

The breaking load(F)=50 kgf

Breaking extension(e)=8%

The velocity of lower jaw(v)=0.50 cm/s

Pendulum swings by=30 deg from its normal position

The change in machine rate of loading()=? in kgf/cm

By formula-

Where, is the pendulum swings angle

kgf/cm

i.e.,

The change in machine rate of loading=173.2 kgf/cm (Ans)