**Common Data Questions**

Assume that the “standard machine rate of loading” of a commercial tensile testing machine working on pendulum lever principle is 200 kgf/cm. The breaking load and extension of a sample tested at a gauge length of 20 cm is 50 kgf and 8% respectively. The velocity of the lower jaw is 0.50 cm/s.

###### Question 75 (Textile Engineering & Fibre Science)

The time required to break the sample in seconds is

(A) | 3.7 |

(B) | 4.3 |

(C) | 5.2 |

(D) | 6.3 |

**[Show Answer]**

Option A is correct

Given in the question-

Standard machine rate of loading()=200 kgf/cm

Gauge length=20 cm

The breaking load(F)=50 kgf

Breaking extension=8%

i.e ,

Breaking extension=gauge length x 8%

Breaking extension(e)=20 x 8/100

Breaking extension(e)=1.6 cm

The velocity of lower jaw(v)=0.50 cm/s

Pendulum swings by=30 deg from its normal position

Time require to break the sample(t)=?

By formula-

Time(t)=3.7 sec (Ans)