GATE (TF) Textile 2008 Question Paper Solution | GATE/2008/TF/76

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Question 76 (Textile Engineering & Fibre Science)

A polymer melt (density = 0.95 g/cm3), is being spun through a spinneret of 1000 holes. The mass throughput rate and take-up speed are 300 g/min. and 300 m/min. respectively.
The nominal denier of the single filament is

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Option B is correct.

Given in the question-

No. of spinneret holes=1000

Mass throughput rate=300 g/min

Take-up speed=300m/min

Polymer melt density=0.95 g/cm3

Normal denier of single filament=?

Denier=\frac{Mass throughput rate}{Take-up speed} \times 9000

Denier=\frac{300}{300} \times 9000

Denier=1 \times 9000

Denier of multifilament=9000

Denier of single filament=Denier of multi filament/No. of holes in spinneret

Denier of single filament=9000/1000

Denier of single filament=9 (Ans)

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