GATE (TF) Textile 2009 Question Paper Solution | GATE/2009/TF/25

Question 25 (Textile Engineering & Fibre Science)

The general solution of the differential equation

    \[x^2\frac{d^2y}{dx^2}+2x\frac{dy}{dx}-\frac{y}{x^2}=0\]

(A)y=c_1cosx+c_2sinx
(B)y=c_1e^x+c_2e^{-x}
(C)y=\left ( c_1 + \frac{c_3}{x} \right )e^{(1/x)}
(D)y=(c_1+c_2x)e^x
[Show Answer]

Option C is correct

    \[x^2\frac{d^2y}{dx^2}+2x\frac{dy}{dx}-\frac{y}{x^2}=0\]

D^2+2D

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