Common Data Questions
Ten Thousand metre of polyester fabric is to be dyed to 2% depth of shade by continuous method. The width of the fabric is 1.5 m and mass per unit per area is 200 g/m2. Assume the specific gravity of the dye liquor to be 1.0 and a wet pickup of 80% after padding.
Question 56 (Textile Engineering & Fibre Science)
The concentration (gpl) of the dye bath would be
| (A) | 40 |
| (B) | 35 |
| (C) | 30 |
| (D) | 25 |
[Show Answer]
Option D is correct
Given in the question-
Length of fabric=10000 meter
Dye depth=2%
Width of fabric=1.5 m
Mass per unit area=200 g/m2
Wet pick up=80%
Specific gravity=1.0
The volume of the liquor in litres used on the fabric would be=?
Weight of fabric=Mass per unit area x Length of fabric x Width of fabric
Weight of fabric=200 x 10000 x 1.5
Weight of fabric=3000000 gm
Weight of fabric=3000 kg
Weight of dye=3000 x 2%
=60 kg
By formula-
Wet pick-up%=Weight of dye on liquor x 100/Weight of fabric
80=Weight of dye on liquor x 100/3000
Volume of Liquor in litres=2400
By formula-
Concentration=Wt of dye in gm/Volume of Liquor in litres
Concentration=60 x 1000/2400
Concentration=60 x 1000/2400
Concentration of dye bath=25 g/l (Ans)