GATE (TF) Textile 2011 Question Paper Solution | GATE/2011/TF/17

Question 17 (Textile Engineering & Fibre Science)

If the 50% span length of a cotton fiber is 13.5 mm and the uniformity ratio is 45%, then 2.5% span length of this fibre in mm would be

(A)10
(B)15
(C)30
(D)35
[Show Answer]

Given in the question-

50% span length(50 %SL)=13.5 mm

Uniformity ratio(UR)=45%

2.5% span length(2.5% SL)=?

By formula-

UR percentage=\frac{50 percentage span length}{2.5 percentage span length}\times 100

45 percentage=\frac{13.5}{2.5 percentage span length}\times 100

0.45 percentage=\frac{13.5}{2.5 percentage span length}

2.5 percentage span length=\frac{13.5}{0.45}

2.5 percentage span length=30 mm (Ans)

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