GATE (TF) Textile 2011 Question Paper Solution | GATE/2011/TF/53

Linked Answer Question

For a shuttle loom, the radius of crank and length of the connecting rod to the sley are 10 cm and 40 cm, respectively.

The ratio of sley acceleration at the front centre and back centre of the loom is

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Given in the question-

Radius of crank(r)=10 cm

Length of connecting rod(l)=40 cm

By formula-

$Sley eccentricity(e)=\frac{Radius of crank}{Length of connecting rod}$

$Sley eccentricity(e)=\frac{r}{l}$

$Sley eccentricity(e)=\frac{10}{40}$

Sley eccentricity(e)=0.25

Acceleration in front centre(a1)=r(1+e)

a1=10 x (1+0.25)

a1=10 x 1.25

a1=12.5

Acceleration in back centre(a2)=-r(1-e)

a2=-10 x (1-0.25)

a2=-10 x 0.75

a2=-7.5

Now,

$\frac{Acceleration in front centre(a1)}{Acceleration in back centre(a2)}=\frac{12.5}{-7.5}$

$\frac{Acceleration in front centre(a1)}{Acceleration in back centre(a2)}=-1.67$ (Ans)