Four percent ass on (owf) of a finish is required on a fabric having a weight of 0.60 kg/m. Consider the wet picks up as 80%, speed of the fabric as 90 m/min and density of liquor as 1.2 g/ml.
Question 54 (Textile Engineering & Fibre Science)
Concentration (%) of the finish required in the bath is
| (A) | 0.2 |
| (B) | 3.2 |
| (C) | 5.0 |
| (D) | 32 |
[Show Answer]
Given in the question-
Add-on %=4 %
fabric weight=0.60 kg/m
Wet pick-up%=80%
Speed of the fabric=90 m/min
Density of liquors=1.2 g/ml
Concentration % of the finish required in the bath=?
Firstly we have to calculate-
Fabric weight=0.60 kg/m x 90 m/min
Fabric weight=54 kg/min
Weight of finish=fabric weight x add-on
Weight of finish=54 x 4%
Weight of finish=54 x 4/100
Weight of finish=216/100
Weight of finish=2.16 kg/min
or
Finish consumed in kg/min=2.16
Formula-
Wet pick-up=Add-on(A)/Concentration(C)
or
Wet pick-up=Liquor weight/Weight of fabric
0.8=Liquor weight/54
Liquor weight=0.8 x 54
Liquor weight=43.2 kg/min
Formula-
Concentration%=(Weight of finish/liquor weight)x100
Concentration%=(2.16/43.2) x 100
Concentration%=0.05 x 100
Concentration%=5% (Ans)