GATE (TF) Textile 2014 Question Paper Solution | GATE/2014/TF/48

Question 48 (Textile Engineering & Fibre Science)

A 60.5 tex yarn with an unevenness CV of 10% is produced from 0.5 tex polyester fibre. The index of irregularity of the yarn, accurate to one decimal place, will be ………………..

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Given in the question–

Tex of yarn=60.5

CV_eff(%)=10

Tex of polyester fibre=0.5

Index of irregularity of yarn=?

Calculation–

Index of irregularity=CV _eff/CV _lim

CV_lim=100/ $\sqrt n$
Where, n is the number of fibres in the yarn cross section

n=Tex of yarn/tex of fibre

n=60.5/0.5

n=121

Now,
CV_lim=100/ $\sqrt 121$

CV_lim=100/11

CV_lim(%)=9.09

Index of irregularity=10/9.09

Index of irregularity=1.10 (Answer)

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