###### Question 08 (General Aptitude)

In the given figure angle Q is a right angle, PS:QS=3:1, RT:QT=5:2 and PU:UR = 1:1. If area of triangle QTS is 20 cm^{2} , then the are of triangle PQR in cm^{2} is _**_280_**_.

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Area of triangle PQR=

Area of triangle PQR=

Area of triangle PQR=

Area of triangle PQR=

Area of triangle PQR=

Area of triangle PQR= (Ans)