GATE (TF) Textile 2015 Question Paper Solution | GATE/2015/TF/14

Question 14 (Textile Engineering & Fibre Science)

If A= \begin{bmatrix} 3 & 0 & 0\\ 0 & 4 & 0\\ 0 & 0 & \frac{1}{12}\end{bmatrix}, then determinant A^{-1} is __1__.

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A= \begin{bmatrix} 3 & 0 & 0\\ 0 & 4 & 0\\ 0 & 0 & \frac{1}{12}\end{bmatrix}
\left |A \right |=3(4\times\frac{1}{12})-0+0
\left |A \right |=1
\left |A^{-1} \right |=\frac{1}{A}
\left |A^{-1} \right |=1 (Ans)

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