GATE (GA) Textile 2016 Question Paper Solution | GATE/2016/GA/05

Question 05 (General Aptitude)

If $\left | 9y-6 \right |=3$ , then $\left | y^2-\frac{4y}{3} \right |$ is __

(A)	0
(B)	$+\frac{1}{3}$
(C)	$-\frac{1}{3}$
(D)	undefined

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$\left | 9y-6 \right |=3$ , then $\left | y^2-\frac{4y}{3} \right |=?$
Firstly we will find out the value of the y.
$\left | 9y-6 \right |=3$
i.e.
-3<9y-6<3
$\frac{1}{3}<y<1$
Now,
$\left | y^2-\frac{4y}{3} \right |$
At y=1
$\left | y^2-\frac{4y}{3} \right |=-1$
At y= $\frac{1}{3}$
$\left | y^2-\frac{4y}{3} \right |=\frac{-11}{27}=-0.4$

i.e. the value of the function lie between -0.4 and -0.1, it is $\frac{-1}{3}$ (Ans)

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