Question 20 (Textile Engineering & Fibre Science)
A fabric specimen of original length 75 mm is stretched to a length of 120 mm and after removal of the load the length reduces to 95 mm. The elastic recovery (%) of the fabric specimen is __55:56__.
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Given in the question-
Original length of fabric=75mm
Total length of specimen after stretching(L)=120mm
i.e. total stretched length =120-75
Total stretched length =45 mm
After removal of load length reduced to length(l)=95mm
i.e.,Remaining length of specimen=95mm
Total extended length after recovery(l‘)=95-75
l‘ =20 mm
And
Total elastic length of specimen=45-20
Total elastic length of specimen=25 mm
Formula:
Elastic recovery%=55.55 (Answer)