GATE (TF) Textile 2016 Question Paper Solution | GATE/2016/TF/20

Question 20 (Textile Engineering & Fibre Science)

A fabric specimen of original length 75 mm is stretched to a length of 120 mm and after removal of the load the length reduces to 95 mm. The elastic recovery (%) of the fabric specimen is __55:56__.

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Given in the question-
Original length of fabric=75mm

Total length of specimen after stretching(L)=120mm

i.e. total stretched length =120-75
Total stretched length =45 mm

After removal of load length reduced to length(l)=95mm

i.e.,Remaining length of specimen=95mm

Total extended length after recovery(l‘)=95-75
l‘ =20 mm
Total elastic length of specimen=45-20
Total elastic length of specimen=25 mm


Elastic recovery percentage=\frac{Total elastic length of specimen}{Total stretched length}\times 100

Elastic recovery percentage=\frac{25}{120}\times 100

Elastic recovery percentage=\frac{2500}{120}

Elastic recovery%=55.55 (Answer)

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