Question 39 (Textile Engineering & Fibre Science)
The final yarn count required from a ring frame is 36s Ne with 28 TPI. The twist contraction during spinning is 3%. If the feed roving count is 2s Ne, the mechanical draft required in the ring frame will be __18.40 : 18.65__.
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Given in the question–
The yarn count=36s Ne
TPI=28
Twist contraction=3%
Feed roving count=2s Ne
Mechanical draft=?
Let, initial yarn count =X
Then,
X(1-(3%/100))=36
X(1-0.03)=36
X(0.97)=36
X=36/0.97
Delivery count(X)=37.11
Formula:
Mechanical draft=Delivery count /Feed count
=37.11/2
Mechanical draft=18.55 (Answer)