GATE (TF) Textile 2018 Question Paper Solution | GATE/2018/TF/48

Question 48 (Textile Technology & Fibre Science)

A shuttle loom having 1.75 m reed width is running at 180 rpm. The shuttle enters and leaves the shed at 120^o and 240^o angular positions of crankshaft, respectively. If length of the shuttle is 0.25 m, then the mean velocity (in m/s) of the shuttle within the shed is __18.0 to 18.2__.

[Show Answer]

Write Here

Given in the question–
Reed width=1.75 m

Loom speed=180 rpm

The shuttle entre the shed at 120^o

The shuttle leaves the shed at 240^o

Length of shuttle=0.25 meter

Mean velocity(m/s)=?

Calculation–

By formula:

$Mean velocity(v)=\frac{(Reed width\dotplus length of shuttle)\times6\times loom speed}{(\theta_2-\theta_1)}$

$Mean velocity(v)=\frac{(1.75\dotplus 0.25)\times6\times180}{(240^o-120^o)}$

$Mean velocity(v)=\frac{2\times6\180}{120}$

$Mean velocity(v)=\frac{2\times6\180}{120}$

$Mean velocity(v)=\frac{2160}{120}$

$Mean velocity(m/s)=18.0$ (Answer)

Previous Question

Next Question

Frequently Asked Questions | FAQs

GATE Textile Engineering and Fibre Science (TF) Question Papers | GATE Textile Question Answer | GATE Textile Solved Question Papers | GATE Textile Papers | GATE Textile Answer Key