Question 24 (Textile Engineering & Fibre Science)
A padding mangle is processing a fabric at 1320 m/h. The bottom bowl of the mangle is rotating at 25 rpm. Assuming zero slippage at the nip, the diameter (cm) of this bowl is __28.00 to 29.00__.
[Show Answer]
Write Here
Given in the question:
Padding mangle speed(v)=1320 m/h
v=1320/60 meter/min
v=22 m/min
Revolution speed of bottom bowl of mangle(n)=25 rev/min(rpm)
Diameter of the bowl(D)=?
Calculation by formula:
Padding mangle speed(v)=
x Diameter of bowl x revolution speed of bowl(n)
22=3.14 x D X 25
D=0.2802 meter
D=0.2802 x 100 cm
D=28.02 cm (Answer)