Question 50 (Textile Engineering & Fibre Science)
A cotton fibre has degree of cell wall thickening of 0.9 and perimeter of 40
. The actual cross-sectional area of the wall
of the fibre (rounded off to 1 decimal place) is __112.0 to 117.0__.
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Given:
Degree of cell wall thickening ()=0.9
Perimeter(P)=40 .
A’=
Formula:=A/A’
Where, A is actual cross sectional area , A’ is standard cross sectional area and P is the perimeter=
(Area)A=114.65 (Answer)