GATE (TF) Textile 2020 Question Paper Solution | GATE/2020/TF/51

Question 51 (Textile Engineering & Fibre Science)

A fabric with mass per unit area 250 g/m² has flexural rigidity of 275 $\mu N\cdot m$ . The bending length (mm) of the fabric (rounded off to 2 decimal places) is __46.00 to 50.00__.

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Given in the question–

Fabric mass per unit area(W)=250 g/m²

Flexural regidity(G)=275 $\mu N\cdot m$

Bending length of the fabric(C)=?

Formula:

G=W x C³ ,

Where, G is flexular regidity , C is bending length

275*10^-6*10³/9.8=250 x C³ ( $1\mu N$ =10^-6 N and 1 kg=1000 gm)

C³ =(275*10^-3)/(9.8*250)

C³ =0.1122*10^-3

C= $\sqrt[3]{0.1122}$ *10^-1

C=0.4823*10^-1 meter

C=0.4823*10^-1 *10³ mm

C=0.4823 *10² mm

C=48.23 mm (Answer)

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