Question 53 (Textile Engineering & Fibre Science)
Under a load of 500 cN, the extension of a yarn of 300 mm length us 10%. If the elastic recovery is 90%, then the length (mm) of the yarn after removal of load is __303__.
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Data given in the question:
Load(F)=500 cN
Extension(e)=10%
Length of yarn(L)=300 mm
Elastic recovery=90%
Length of yarn after removal of load(L2)=?
Calculation:
Yarn length after 10% extension at 500cN load(L1)=L+(L*10/100)
L1=300+(300*10/100)
L1=330 mm
i.e. Extended length(l)=L1-L
=330-300
l=30 mm
Extended length of yarn after 90% elastic recovery(l2)={l-(l*90/100)}
l2={30-(30*90/100)}
l2=3 mm
Length of yarn after removal of load(L2)=L+l2
Length of yarn after removal of load(L2)=300+3
Length of yarn after removal of load(L2)=303 mm (Answer)