GATE (TF) Textile 2021 Question Paper Solution | GATE/2021/TF/55

Question 55 (Textile Technology & Fibre Science)

Consider the following isotherms at equilibrium for two disperse dyes D1 and D2 dyed on polyester. If the partition coefficient of those are K1 and K2 respectively, the value of \frac{K_2}{K_1} is __4__.

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Given in the question:

Concentration of dye D1 in fibre(df)=5 g/kg
Concentration of dye D1 in solution(ds)=0.1 g/L

Concentration of dye D2 in fibre(df)=10 g/gm
Concentration of dye D2 in solution(ds)=0.05 g/L


Partition coefficient(K)=Concentration of dye in fibre(df)/Concentration of dye in solution(ds)

K1=Concentration of dye D1 in fibre(df)/Concentration of dye D1 in solution(ds)
K1 =5/0.1
K1=50 L/kg

K2=Concentration of dye D2 in fibre(df)/Concentration of dye D2 in solution(ds)

K2=200 L/kg


K2/K1=4 (Answer)

Solution is to written here

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