GATE (TF) Textile 2010 Question Paper Solution | GATE/2010/TF/53

If the diameter of the above yarn (as in question – 52) is 0.28 mm, the twist angle will be approximately

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Given in the question-

Diameter of the yarn(D)=0.28 mm

D=0.28 /10 cm

D=0.028 cm
Twist angle=?

By twist angle geometry-

$tan \alpha=\pi \times D \times TPCM$

Where $\alpha$ is the twist angle

$tan \alpha=3.14 \times 0.028 \times TPCM$

From question no. 52,solution-

We have calculated TPCM=6.83

$tan \alpha=3.14 \times 0.028 \times 6.83$

$tan \alpha=0.60$

$\alpha= tan^-1 (0.60)$

$\alpha=30.96$

$\alpha=30.0$

Option C is correct approximately.