GATE (TF) Textile 2015 Question Paper Solution | GATE/2015/TF/50

Question 50 (Textile Engineering & Fibre Science)

The groove drum in a random winder makes five revolutions for one double traverse. If the drum and package diameters are 10 cm and 5 cm, respectively, the wind per double traverse would be __10__.

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Given in the question–

Groove drum revolutions per one double traverse(K)=5

Drum diameter(D_d)=10 cm

Package diameter(D_p)=5 cm

Wind per double traverse(TR)=?

Formula:

Surface speed of drum=Surface speed of package

$\pi \times D_d \times N_d=\pi \times D_p \times N_p$

$D_d \times N_d=D_p \times N_p$

$D_d \times N_d=D_p \times N_p$

N_d/N_p=D_p/D_d

Drum constant(K)=N_d/N_t

T.R.=N_p/N_t

Now,

K/T.R.=N_d/N_t/N_p/N_t

K/T.R.=(N_dN_t/N_pN_t)

K/T.R.=(N_d/N_p)

K/T.R.=(N_d/N_p)

K/T.R.=D_p/D_d

5/T.R.=5/10

Wind per double traverse(T.R.)=10 (Answer)

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