###### Question 44 (Textile Engineering & Fibre Science)

Let a cheese of 160 mm traverse length be wound on a rotary traverse machine having a drum of 75 mm diameter and 2.5 crossings. If the drum rotates at 3250 rpm, then the coil angle, in degrees, accurate to one decimal place, is _**_73.5 to 76.0_**_.

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**Solution:****Given in the question**–

Traverse length of cheese(**L**)=**160mm**

=160 x 10^{-3} meter

Dia of drum(**D _{d}**)=

**75 mm**

=75 x 10

^{-3}meter

No. of crossings=

**2.5**

Drum rotational speed(

**N**)=

_{d}**3250rpm**

Coil angle()=

**?**

**Formula**:

Where, Vt=Traverse speed , Vs=Package Surface speed and =coil angle

Where,

**N**is traverse rotational speed

_{t}Traverse ratio=2 x No. of crossings

Traverse ratio=2 x 2.5

**Traverse ratio=5**

Now,

**Traverse speed(V**

_{t})=208 m/minAnd

**(Package surface speed=Drum surface speed)**

**V**

_{s}=765.4 m/min(

**Answer)**