GATE (TF) Textile 2021 Question Paper Solution | GATE/2021/TF/52

Question 52 (Textile Technology & Fibre Science)

A woven fabric with areal density of 300 g/m² is tested by strip tensile test method, keeping the specimen width as 5 cm and gauge length as 25 cm. If the breaking load is 900 N, the tenacity (cN/tex) of the fabric is
__6__.

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Given:

Areal density of woven fabric=300 g/m²
Specimen width=5 cm = 5X10^-2 m
Breaking load=900 N
Tenacity(cN/tex)=?

Now,
g/m =300x5x10^-2
gram/meter =15 ,

i.e 1 meter have =15 gm ,
So, 1000 meter have =15*1000

Tex=15000 (Tex is mass in gm of 1000 meter length=gm/1000 meter)

Now by formula:

Tenacity= $\frac{Breaking \: load}{tenacity}$

Tenacity= $\frac{900}{15000}$ $\frac{N}{tex}$

Tenacity= $\frac{900*100}{15000}$ $\frac{cN}{tex}$

Tenacity= $\frac{90000}{15000}$ $\frac{cN}{tex}$

Tenacity=6 $\frac{cN}{tex}$ (Answer)

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