Question 48 (Textile Engineering & Fibre Science)
In a drum-driven winder, the grooved drum having a width of 20 cm is rotating at 1000 rpm. If the drum makes 5 revolutions per double traverse, the traverse speed (m/min) is __80__.
[Show Answer]
Write Here
Given in the question-
Grooved drum width(Traverse length,L)=20 cm
L=0.20 mtr
Drum revolutions(Np)=1000 rpm
Traverse ratio(T.R.)=5 rev/double traverse
Traverse speed(Vt)=?
Formula:
T.R.=Np/Nt ,
Where N p is package revolutions speed and N t is traverse revolutions
Here,
N t=Np / T.R.
N t=1000 / 5
N t=200 rev/min
Now by formula–
Vt=2 x L x Nt
Vt=2 x 0.20 x 200
Vt=80 m/min (Answer)